If these ideas are new, begin with:
Understand the idea
Ordered structures support predecessor, successor, insertion, deletion, and ranges. Balanced search trees guarantee logarithmic height; subtree counts add rank/select. Sorted arrays have fast search but linear insertion shifts.
Work through an example
Coordinate-compressed Fenwick counts can answer ranks when all possible coordinates are known in advance. Truly online unseen keys need a different ordered structure or rebuilding.
Time and space complexity
Balanced ordered operations O(log n); sorted-list insertion O(n); offline compression O(n log n).
Why it works
Every operation preserves key ordering and any augmented subtree/block summaries.
Common mistakes
- Python bisect is not a balanced tree.
- Compression ranks preserve order but not coordinate gaps.
Chapter lab · Python implementation
Range structures trade preprocessing and memory for repeated queries and updates. The lab implements a Fenwick sum tree, an iterative segment sum tree, and a lazy range-add/range-sum tree. Their external ranges are half-open. Coordinate compression preserves order for sparse coordinates but does not preserve physical distances.
This shared lab connects the chapter's topics. Follow the current lesson's worked example first, then trace the complete implementation. Additional algorithms described in topic exercises are variations you can implement independently.
class Fenwick:
def __init__(self,n):
if n<0: raise ValueError('nonnegative size required')
self.n=n; self.tree=[0]*(n+1)
def add(self,index,delta):
if not 0<=index<self.n: raise IndexError(index)
i=index+1
while i<=self.n:
self.tree[i]+=delta; i+=i&-i
def prefix(self,end):
if not 0<=end<=self.n: raise IndexError(end)
result=0; i=end
while i:
result+=self.tree[i]; i-=i&-i
return result
def query(self,left,right):
if not 0<=left<=right<=self.n: raise IndexError('range')
return self.prefix(right)-self.prefix(left)
class Segment:
def __init__(self,values):
self.n=len(values); self.tree=[0]*self.n+list(values)
for i in range(self.n-1,0,-1):
self.tree[i]=self.tree[2*i]+self.tree[2*i+1]
def set(self,i,value):
if not 0<=i<self.n: raise IndexError(i)
i+=self.n; self.tree[i]=value
while i>1:
i//=2; self.tree[i]=self.tree[2*i]+self.tree[2*i+1]
def query(self,left,right):
if not 0<=left<=right<=self.n: raise IndexError('range')
left+=self.n; right+=self.n; answer=0
while left<right:
if left&1: answer+=self.tree[left]; left+=1
if right&1: right-=1; answer+=self.tree[right]
left//=2; right//=2
return answer
class LazySum:
def __init__(self,n):
if n<1: raise ValueError('positive n required')
self.n=n; self.tree=[0]*(4*n); self.lazy=[0]*(4*n)
def apply(self,node,lo,hi,delta):
self.tree[node]+=delta*(hi-lo); self.lazy[node]+=delta
def push(self,node,lo,hi):
if self.lazy[node] and hi-lo>1:
mid=(lo+hi)//2
self.apply(2*node,lo,mid,self.lazy[node])
self.apply(2*node+1,mid,hi,self.lazy[node])
self.lazy[node]=0
def update(self,left,right,delta):
if not 0<=left<=right<=self.n: raise IndexError('range')
def visit(node,lo,hi):
if right<=lo or hi<=left: return
if left<=lo and hi<=right:
self.apply(node,lo,hi,delta); return
self.push(node,lo,hi); mid=(lo+hi)//2
visit(2*node,lo,mid); visit(2*node+1,mid,hi)
self.tree[node]=self.tree[2*node]+self.tree[2*node+1]
visit(1,0,self.n)
def query(self,left,right):
if not 0<=left<=right<=self.n: raise IndexError('range')
def visit(node,lo,hi):
if right<=lo or hi<=left: return 0
if left<=lo and hi<=right: return self.tree[node]
self.push(node,lo,hi); mid=(lo+hi)//2
return visit(2*node,lo,mid)+visit(2*node+1,mid,hi)
return visit(1,0,self.n)Run and test the lab
Copy the implementation and these assertions into a Python 3 file and run it. An assertion failure means the actual result differs from the expectation. Add the current topic's exercise and boundary tests to deepen your understanding.
f=Fenwick(4)
for i,x in enumerate([2,1,3,4]): f.add(i,x)
assert f.query(1,4)==8
f.add(2,5); assert f.query(0,4)==15
s=Segment([2,1,3,4]); assert s.query(1,4)==8
s.set(2,8); assert s.query(0,4)==15
l=LazySum(5); l.update(1,4,3); l.update(2,5,-1)
assert l.query(0,5)==6 and l.query(2,4)==4
assert l.query(0,0)==0Does compressing [10,1000] to [0,1] preserve distance?
Further reading
Original documentation for the implementation details used in this chapter.
Fenwick trees Segment trees