If these ideas are new, begin with:
Understand the idea
FIFO means first-in-first-out. Enqueue at the back and dequeue at the front. This order supports fair work processing and breadth-first search.
Work through an example
Enqueue A,B,C then dequeue returns A, leaving B,C. A stack would return C and process tasks in a different order.
Time and space complexity
Deque endpoint operations O(1); n pending items use O(n) memory.
Why it works
The front is the oldest pending item.
Common mistakes
- list.pop(0) costs O(n) shifting.
- Empty queues need a defined error or sentinel behavior.
Chapter lab · Python implementation
Queues process the oldest pending item first. Python deque supports efficient operations at both ends; list.pop(0) shifts a packed list. The lab maintains a decreasing deque of candidate indices for each fixed-size window maximum, keeping expiration separate from dominance.
This shared lab connects the chapter's topics. Follow the current lesson's worked example first, then trace the complete implementation. Additional algorithms described in topic exercises are variations you can implement independently.
from collections import deque
def window_max(values,k):
if not 1<=k<=len(values):
raise ValueError('invalid k')
candidates=deque()
output=[]
for i,x in enumerate(values):
while candidates and candidates[0]<=i-k:
candidates.popleft()
while candidates and values[candidates[-1]]<=x:
candidates.pop()
candidates.append(i)
if i>=k-1:
output.append(values[candidates[0]])
return outputRun and test the lab
Copy the implementation and these assertions into a Python 3 file and run it. An assertion failure means the actual result differs from the expectation. Add the current topic's exercise and boundary tests to deepen your understanding.
assert window_max([1,3,-1,-3,5,3,6,7],3)==[3,3,5,5,6,7]
assert window_max([2,2,2],2)==[2,2]
assert window_max([-4],1)==[-4]Which task leaves after enqueueing A then B?
Further reading
Original documentation for the implementation details used in this chapter.
Python deque