If these ideas are new, begin with:
Understand the idea
Traversal visits each element; an update writes a new value at a known position. Separate the index from the value and identify the processed prefix.
Work through an example
Doubling [2,5,1] in place gives [4,5,1]→[4,10,1]→[4,10,2]. The unprocessed suffix remains unchanged.
Time and space complexity
Θ(n) traversal, O(1) auxiliary state for indexed updates.
Why it works
After index i, every element through i has been doubled exactly once.
Common mistakes
- Assigning to a loop variable does not replace list integers.
- Inserting during traversal changes positions.
Chapter lab · Python implementation
Arrays make positions directly accessible. Our lab compacts a sorted list: read examines input; write marks the next output slot. Python lists are resizable arrays of references. Fixed-width address diagrams illustrate slots, rather than promising contiguous Python objects.
This shared lab connects the chapter's topics. Follow the current lesson's worked example first, then trace the complete implementation. Additional algorithms described in topic exercises are variations you can implement independently.
def compact_sorted(values):
write = 0
for read in range(len(values)):
if write == 0 or values[read] != values[write-1]:
values[write] = values[read]
write += 1
return write
def transpose(matrix):
if not matrix:
return []
cols = len(matrix[0])
if any(len(row) != cols for row in matrix):
raise ValueError('rectangular matrix required')
return [[matrix[r][c] for r in range(len(matrix))]
for c in range(cols)]Run and test the lab
Copy the implementation and these assertions into a Python 3 file and run it. An assertion failure means the actual result differs from the expectation. Add the current topic's exercise and boundary tests to deepen your understanding.
a=[1,1,2,2,3]; k=compact_sorted(a)
assert a[:k]==[1,2,3]
assert compact_sorted([])==0
assert transpose([[1,2,3],[4,5,6]])==[[1,4],[2,5],[3,6]]
assert transpose([])==[]